A ball is thrown at an angle 45.0° above the horizontal from ground level with an initial velocity of 20.0 m/s. What is the range of the ball?
A) 20.0 m
B) 40.8 m
C) 19.6 m
D) 34.4 m
E) None of the other choices is correct.

Question

Quizplus · Accepted Answer

The range R of a projectile launched at an angle θ with initial velocity v is given by the formula R = (v^2 * sin(2θ)) / g, where g is the acceleration due to gravity (9.8 m/s²). For θ = 45° and v = 20.0 m/s, R = (20.0^2 * sin(90°)) / 9.8 = 40.8 m.

A Ball Is Thrown at an Angle 45