A 50.0-kg crate is being pulled along a horizontal, smooth surface. The pulling force is 10.0 N and is directed 20.0° above the horizontal. What is the acceleration of the crate? A) 0.0684 m/s² B) 0.188 m/s² C) 0.200 m/s² D) 0.376 m/s² E) 0.0728 m/s²

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Quizplus · Accepted Answer

The horizontal component of the force is $10.0 \, \text{N} \times \cos(20.0^\circ)$. The acceleration is given by $a = \frac{F_{\text{horizontal}}}{m} = \frac{10.0 \, \text{N} \times \cos(20.0^\circ)}{50.0 \, \text{kg}}$, which calculates to approximately 0.188 m/s².

A 500-Kg Crate Is Being Pulled Along a Horizontal, Smooth Surface