A 30.0-kg object slides down a slope which is inclined 27.0° to the horizontal. What is the normal force on the object?
A) 133 N
B) 171 N
C) 262 N
D) 387 N
E) 398 N

Question

Quizplus · Accepted Answer

The normal force is calculated using the component of the gravitational force perpendicular to the slope: $ F_n = mg \cos(\theta) $. Here, $ m = 30.0 \, \text{kg} $, $ g = 9.8 \, \text{m/s}^2 $, and $ \theta = 27.0^\circ $. So, $ F_n = 30.0 \times 9.8 \times \cos(27.0^\circ) \approx 262 \, \text{N} $.

A 300-Kg Object Slides Down a Slope Which Is Inclined 27