A 50.0-kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 250 N at an angle of 32.0° above the horizontal. The coefficient of kinetic friction between the box and the surface is 0.350. What is the acceleration of the box? A) 0.638 m/s² B) 1.74 m/s² C) 3.16 m/s² D) 6.31 m/s² E) 8.53 m/s²

Question

Quizplus · Accepted Answer

The horizontal component of the pulling force is 250 N * cos(32°). The normal force is reduced by the vertical component of the pulling force, 250 N * sin(32°). The frictional force is the coefficient of kinetic friction times the normal force. Subtract the frictional force from the horizontal component of the pulling force to find the net force, then divide by the mass to find the acceleration.

A 500-Kg Box Is Being Pulled Along a Horizontal Surface by by Means