Diff: 1 Var: 5 Page Ref: Sec. 6-2
-A mass of 40.0 grams is attached to a vertical spring with a spring constant k = 20.0 N/m and lowered slowly until the spring stops stretching. How much does the spring stretch?
A) 0.00200 m
B) 0.0196 m
C) 0.0816 m
D) 0.800 m
E) 0.200 m

Question

Quizplus · Accepted Answer

The formula for the displacement of a spring is given by:

x = F/k

where:
x = displacement
F = force applied
k = spring constant

Using the given information, we can find the force applied to the spring:

F = mg = (0.040 kg)(9.81 m/s²) = 0.392 N

Substituting this into the formula for x, we get:

x = F/k = (0.392 N)/(20.0 N/m) = 0.0196 m

Therefore, the spring stretches by 0.0196 m. The best choice is B.