An object of 1.0 kg mass is pulled up an inclined plane by a constant force of 10 N that causes a displacement of 0.50 m. The angle of inclination with the horizontal is 30°. Neglect friction and use g = 10 m/s². What is the work done by the 10 N force on the object along the inclined plane? A) 4.3 J B) 4.3 kg m/s² C) 5.0 J D) 2.5 J

Question

Quizplus · Accepted Answer

The work done by a constant force is given by the formula W = Fd cos(θ), where F is the force magnitude, d is the displacement magnitude, and θ is the angle between F and d. In this problem, the force is 10 N, the displacement is 0.50 m along the inclined plane, and the angle between them is 30°. Therefore, the work done by the force is:

W = 10 N * 0.50 m * cos(30°) = 5.0 J

(Note that the mass is not needed to calculate the work done here, because it is not a factor in the formula for work done by a constant force.)

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