An object approaches the bottom of a ramp, point A. It goes up the ramp and turns around at point B, which is 40.0 m above A. The ramp makes an angle of 30.0° with the horizontal. What is the speed of the object at point A? Neglect friction and use g = 10.0 m/s².

Question

Quizplus · Accepted Answer

Using conservation of energy: 
potential energy at A = kinetic energy at B 
mgh = 1/2mv^2 
Solve for v: 
v = sqrt(2gh) 
v = sqrt(2(10)(40sin30)) 
v = 28.3 m/s

An Object Approaches the Bottom of a Ramp, Point A It