An object of mass m is moving on a horizontal rough surface. At a certain point it has a speed v m/s and it comes to a stop after traveling 32 m. If the coefficient of friction between the object and the surface is 0.40, what is the value of speed v? Use g = 10 m/s².

Question

Quizplus · Accepted Answer

The work done by friction is equal to the initial kinetic energy. Using the equation $ \mu mg \times 32 = \frac{1}{2}mv^2 $, solve for v: $ v = \sqrt{2 \times 0.40 \times 10 \times 32} = 16 $ m/s.

An Object of Mass M Is Moving on a Horizontal