A 0.330-kg volleyball is dropped from rest. It takes it 1.30 s to reach the ground. What is the magnitude of its momentum just before it hits the ground?
A) 4.21 kg∙m/s
B) 0.429 kg∙m/s
C) 3.24 kg∙m/s
D) 2.11 kg∙m/s
E) 1.18 kg∙m/s

Question

Quizplus · Accepted Answer

Momentum is mass times velocity. The mass of the volleyball is 0.330 kg. The velocity of the volleyball just before it hits the ground can be found using the equation v = gt, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time it takes for the volleyball to reach the ground (1.30 s). Plugging in these values, we get v = 9.8 m/s^2 * 1.30 s = 12.74 m/s. Therefore, the momentum of the volleyball just before it hits the ground is 0.330 kg * 12.74 m/s = 4.21 kg∙m/s.

A 0330-Kg Volleyball Is Dropped from Rest