A child is riding a merry-go-round which completes one revolution every 8.36 s. The child is standing 4.65 m from the center of the merry-go-round. What is the tangential speed of the child?
A) 5.64 m/s
B) 3.49 m/s
C) 0.556 m/s
D) 1.75 m/s
E) 1.80 m/s

Question

Quizplus · Accepted Answer

The tangential speed (v) is calculated using the formula v = 2πr/T, where r is the radius (4.65 m) and T is the period (8.36 s). Substituting the values, v = 2π(4.65)/8.36 ≈ 3.49 m/s.

A Child Is Riding a Merry-Go-Round Which Completes One Revolution