A potter's wheel is rotating at 1.00 rpm. What centripetal force is required to hold a 1.00 g lump of clay in place, 10.0 cm from the axis of rotation? A) 1.10 × 10^-6 N B) 1.20 × 10^-6 N C) 1.30 × 10^-6 N D) 1.40 × 10^-6 N E) 1.50 × 10^-6 N

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Quizplus · Accepted Answer

The centripetal force can be calculated using the formula F = mω²r. First, convert rpm to rad/s: 1 rpm = 2π/60 rad/s. Then, use m = 0.001 kg and r = 0.1 m to find F = 0.001 * (2π/60)² * 0.1 = 1.10 × 10⁻⁶ N.

A Potter's Wheel Is Rotating at 1