The moment of inertia of a uniform rod (about its center) is given by I = ML²/12. What is the kinetic energy of a 120-cm rod with a mass of 450 g rotating about its center at 3.60 rad/s? A) 0.350 J B) 4.20 J C) 0.700 J D) 0.960 J E) 2.10 J

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The kinetic energy of a rotating rod is given by K = (1/2)Iω^2, where I is the moment of inertia and ω is the angular velocity. Substituting the given values, we get:K = (1/2)(ML^2/12)(3.60 rad/s)^2 = (1/2)(0.450 kg)(1.20 m)^2(3.60 rad/s)^2 = 0.350 J

The Moment of Inertia of a Uniform Rod (About Its