The hydrogen atom consists of a proton of mass 1.67 × 10^-27 kg and an orbiting electron of mass 9.11 × 10^-31 kg. In one of its orbits, the electron is 5.3 × 10^-11 m from the proton. What is the mutual attractive gravitational force between the electron and proton? A) 1.8 × 10^-47 N B) 3.6 × 10^-47 N C) 5.4 × 10^-47 N D) 7.0 × 10^-47 N E) 9.3 × 10^-47 N

Question

Quizplus · Accepted Answer

The gravitational force between the electron and proton can be calculated using the formula:

F = G * (m1 * m2) / r^2

where G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the electron and proton, respectively, and r is the distance between them.

Plugging in the given values, we get:

F = (6.67 x 10^-11 N*m^2/kg^2) * [(9.11 x 10^-31 kg) * (1.67 x 10^-27 kg)] / (5.3 x 10^-11 m)^2

F = 3.6 x 10^-47 N

Therefore, the answer is B.

The Hydrogen Atom Consists of a Proton of Mass 1