Consider a closed pipe of length L. What are the wavelengths of the three lowest tones produced by this pipe?
A) 16L, 4L, L
B) 4L, 2L, L
C) 2L, L, L/2
D) 2L, L, 2L/3
E) 4L, 4L/3, 4L/5

Question

Quizplus · Accepted Answer

In a closed pipe, the wavelengths of the harmonics are given by 4L/n, where n is an odd integer. The three lowest tones correspond to n = 1, 3, and 5, resulting in wavelengths of 4L, 4L/3, and 4L/5.

Consider a Closed Pipe of Length L