A refrigerator has an interior volume of 0.500 m³. The temperature inside the refrigerator in 282 K, and the pressure is 101 kPa. If the molecular weight of air is 29 g/mol, what is the mass of air inside the refrigerator?

Question

Quizplus · Accepted Answer

The mass of air inside the refrigerator can be calculated using the ideal gas law:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.We can rearrange this equation to solve for n:n = PV/RTWe can then use the molecular weight of air to convert the number of moles to mass:mass = n * molecular weightPlugging in the given values, we get:n = (101 kPa * 0.500 m^3) / (8.31 J/mol*K * 282 K) = 0.0212 molmass = 0.0212 mol * 29 g/mol = 0.615 gTherefore, the mass of air inside the refrigerator is 0.615 g, which is closest to choice A) 625 g.

A Refrigerator Has an Interior Volume of 0