A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110 kPa. How much work is done by the gas?
A) 3.85 kJ
B) 10.4 kJ
C) 3850 kJ
D) 10.4 MJ
E) 3.85 MJ

Question

Quizplus · Accepted Answer

Work done by the gas is calculated using the formula W = PΔV, where P is the pressure and ΔV is the change in volume. Here, W = 110 kPa * (65.0 L - 30.0 L) = 110 kPa * 35.0 L = 3850 kPa·L. Converting kPa·L to kJ (1 kPa·L = 0.001 kJ), we get 3.85 kJ.

A Gas Expands from an Initial Volume of 30