3.0 moles of gas expand from an initial volume of 0.040 m³ to a final volume of 0.085 m³ while the temperature of the gas is kept fixed at 300 K. How much work is done by the system? A) 5.6 kJ B) 6.6 kJ C) 7.6 kJ D) 8.6 kJ E) 14 kJ

Question

Quizplus · Accepted Answer

The work done by the system during an isothermal expansion can be calculated using the formula W = nRT ln(Vf/Vi). Substituting the given values (n = 3.0 moles, R = 8.314 J/mol·K, T = 300 K, Vi = 0.040 m³, Vf = 0.085 m³), the work done is approximately 5.6 kJ.

30 Moles of Gas Expand from an Initial Volume of 0.040