20.0 L of a monatomic ideal gas at a pressure of 100 kPa expand adiabatically until the volume doubles. What is the pressure in the gas at that point?
A) 31.5 kPa
B) 50.0 kPa
C) 200 kPa
D) 317 kPa
E) 400 kPa

Question

Quizplus · Accepted Answer

For an adiabatic process in a monatomic ideal gas, $ P_1 V_1^\gamma = P_2 V_2^\gamma $, where $\gamma = \frac{5}{3}$. Given $ V_2 = 2V_1 $, solve for $ P_2 $: $ P_2 = P_1 (V_1/V_2)^\gamma = 100 \times (1/2)^{5/3} \approx 31.5 $ kPa.

200 L of a Monatomic Ideal Gas at a Pressure