What is the change in entropy when 15.0 g of water at 100°C are turned into steam at 100°C? The latent heat of vaporization of water is 22.6 × 10⁵ J/kg. A) 90.8 J/K B) -90.8 J/K C) 339 J/K D) -339 J/K E) 0 J/K

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Quizplus · Accepted Answer

The change in entropy (ΔS) is calculated using the formula ΔS = Q/T, where Q is the heat absorbed or released and T is the temperature in Kelvin. The mass of water is 0.015 kg, and the latent heat of vaporization is 22.6 × 10^5 J/kg. Therefore, Q = 0.015 kg × 22.6 × 10^5 J/kg = 33900 J. The temperature in Kelvin is 373 K. Thus, ΔS = 33900 J / 373 K = 90.8 J/K.

What Is the Change in Entropy When 15