Two point charges of + 5.00 μC and + 8.00 μC are placed inside a cube of edge length 0.100 m. The net electric flux due to these charges is given by

Question

Quizplus · Accepted Answer

The net electric flux through a closed surface is given by the product of the enclosed charge and the electric constant (ε0). In this case, the two charges are enclosed within the cube, so the net electric flux through the cube is given by:

Φ = Qenc / ε0

where Qenc is the total enclosed charge. The enclosed charge is the sum of the two charges:

Qenc = 5.00 μC + 8.00 μC = 13.00 μC

Plugging this into the equation for net electric flux and using the value for the electric constant:

Φ = (13.00×10^-6 C) / (8.85×10^-12 N^-1 m^-2 C^2) ≈ 1.47×10^16 Nm^2/C

The answer is therefore choice (C).

Two Point Charges of + 5