A + 5.0-μC charge is moved from a negative to a positive plate of a parallel plate capacitor. In moving this charge 0.30 mJ of energy is used. What is the potential difference between the plates of this capacitor?

Question

Quizplus · Accepted Answer

The potential difference (V) can be calculated using the formula V = W/Q, where W is the work done (0.30 mJ = 0.30 x 10^-3 J) and Q is the charge (5.0 μC = 5.0 x 10^-6 C). V = (0.30 x 10^-3 J) / (5.0 x 10^-6 C) = 60 V.

A + 50-μC Charge Is Moved from a Negative to a Positive