An 800 V/m electric field is directed along the +x-axis. If the potential at x = 0 m is 2000 V, what is the potential at x = 2 m?

Question

Quizplus · Accepted Answer

The potential difference between two points is given by the electric field times the distance between the points. In this case, the electric field is 800 V/m and the distance between the points is 2 m, so the potential difference is 800 V/m * 2 m = 1600 V. The potential at x = 0 m is 2000 V, so the potential at x = 2 m is 2000 V + 1600 V = 3600 V.

An 800 V/m Electric Field Is Directed Along the +X-Axis