A 4-μF capacitor has a potential drop of 20 V between its plates. The electric potential energy stored in this capacitor is:

Question

Quizplus · Accepted Answer

The electric potential energy stored in a capacitor is given by:

U = (1/2)*C*(V^2)

where U is the electric potential energy, C is the capacitance, and V is the potential difference between the plates.

Substituting the given values, we get:

U = (1/2)*(4*10^-6)*(20)^2 = 800*10^-6 J = 800 μJ

Therefore, the answer is (D).

A 4-μF Capacitor Has a Potential Drop of 20 V