A light bulb operating at a voltage of 120 V has a resistance of 200 Ω. What is the power? A) 100 W B) 60 W C) 72 W D) 14 × 10^-3 W E) 7.2 W

Name: A light bulb operating at a voltage of 120 V has a resistance of 200 Ω. What is the power? A) 100 W B) 60 W C) 72 W D) 14 × 10 -3 W E) 7.2 W
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Question

Quizplus · Accepted Answer

Using the formula: P = V^2/R, we can find the power (P) in watts.

P = (120 V)^2 / 200 Ω
P = (14400 V^2) / 200 Ω
P = 72 W

Therefore, the power of the light bulb is 72 W. The answer is C.

A Light Bulb Operating at a Voltage of 120 V