An electron moving perpendicular to a magnetic field of 2.2 × 10^-2 T moves in a circle of certain radius. If the electron is moving with a speed of 1.5 × 10⁷ m/s, what is the radius of the circle? A) 1.5 × 10^-3 m B) 2.2 × 10^-4 m C) 2.2 × 10^-3m D) 3.9 × 10^-4 m E) 3.9 × 10^-3 m

Question

Quizplus · Accepted Answer

The radius of the circle is given by the formula r = mv/(qB). For an electron, m = 9.11 × 10^-31 kg and q = 1.6 × 10^-19 C. Substituting the given values, r = (9.11 × 10^-31 kg * 1.5 × 10^7 m/s) / (1.6 × 10^-19 C * 2.2 × 10^-2 T) = 3.9 × 10^-3 m.

An Electron Moving Perpendicular to a Magnetic Field of 2