A straight wire 20 cm long, carrying a current of 4 A, is in a uniform magnetic field of 0.6 T. What is the force on the wire when it is at an angle of 30° with respect to the field?

Question

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by the equation F = BIL sin θ, where F is the force, B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field. In this case, B = 0.6 T, I = 4 A, L = 20 cm = 0.2 m, and θ = 30°. Plugging these values into the equation, we get F = (0.6 T)(4 A)(0.2 m)sin 30° = 0.2 N.

A Straight Wire 20 Cm Long, Carrying a Current of 4