FIGURE 22-7
-A wire in the shape of an "M" lies in the plane of the paper. It carries a current of 2.0 A, flowing from A to E. It is placed in a uniform magnetic field of 0.55 T in the same plane, directed as shown in Figure 22-7. What is the magnitude and direction of the force acting on section CD of this wire?

Question

FIGURE 22-7 
-A wire in the shape of an "M" lies in the plane of the paper. It carries a current of 2.0 A, flowing from A to E. It is placed in a uniform magnetic field of 0.55 T in the same plane, directed as shown in Figure 22-7. What is the magnitude and direction of the force acting on section CD of this wire?

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = I * L * B * sin(θ). For section CD, the current is 2.0 A, the length L is the distance between C and D, B is 0.55 T, and θ is 90 degrees (since the field is in the plane and the wire is perpendicular to it). The force is perpendicular to both the wire and the magnetic field, resulting in a force of 0.070 N out of the page.

FIGURE 22-7 -A Wire in the Shape of an "M" Lies in "M