Two long, parallel wires carry currents of 4.00 A and 6.00 A. If the distance between the wires is 0.400 m, what is the force per unit length between the wires?
A) 2.00 μN/m
B) 5.00 μN/m
C) 12.0 μN/m
D) 16.0 μN/m
E) 38.0 μN/m

Question

Quizplus · Accepted Answer

The force per unit length between two parallel wires carrying currents is given by the equation:

F/L = μ0*I1*I2/(2πd)

where F is the force between the wires, L is the length of the wires, μ0 is the permeability of free space (4π × 10^-7 T·m/A), I1 and I2 are the currents in the wires, and d is the distance between them.

Plugging in the given values, we have:

F/L = (4π × 10^-7 T·m/A) * 4.00 A * 6.00 A / (2π*0.400 m)

Simplifying this expression, we get:

F/L = 3.0 × 10^-5 N/m = 12.0 μN/m

Thus, the answer is C.

Two Long, Parallel Wires Carry Currents of 4