The energy stored in a coil of self-inductance, L, and traversed by current I, is E₁. A second coil is made with the same length of wire, but its radius is twice the radius of the first coil and it is twice as long as the first coil. If the second coil also has twice the current of the first coil, how does the energy stored in the first coil, E₁, compare to the energy stored in the second coil, E₂? A) E₁ = E₂ B) E₁ = E₂/8 C) E₁ = 4E₂ D) E₁ = E₂/2 E) E₁ = E₂/4

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The Answer of The energy stored in a coil of self-inductance, L, and traversed by current I, is E₁. A second coil is made with the same length of wire, but its radius is twice the radius of the first coil and it is twice as long as the first coil. If the second coil also has twice the current of the first coil, how does the energy stored in the first coil, E₁, compare to the energy stored in the second coil, E₂? A) E₁ = E₂ B) E₁ = E₂/8 C) E₁ = 4E₂ D) E₁ = E₂/2 E) E₁ = E₂/4

The Energy Stored in a Coil of Self-Inductance, L, and Traversed