A constant magnetic field of 0.50 T is applied to a rectangular loop of area 3.0 × 10^-3 m². If the area of this loop changes from its original value to a new value of 1.6 × 10^-3 m² in 1.6 s, what is the emf induced in the loop? A) 1.6 × 10^-2 V B) 0 V C) 7.5 × 10^-2 V D) 4.4 × 10^-4 V E) 9.0 × 10^-2 V

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Quizplus · Accepted Answer

The induced emf (ε) can be calculated using Faraday's law of electromagnetic induction: ε = -ΔΦ/Δt, where ΔΦ is the change in magnetic flux. The change in flux ΔΦ = B * ΔA = 0.50 T * (3.0 × 10^-3 m^2 - 1.6 × 10^-3 m^2) = 0.50 T * 1.4 × 10^-3 m^2 = 7.0 × 10^-4 Wb. The time Δt = 1.6 s. Thus, ε = - (7.0 × 10^-4 Wb) / 1.6 s = -4.4 × 10^-4 V. The negative sign indicates the direction of the induced emf, but the magnitude is 4.4 × 10^-4 V.

A Constant Magnetic Field of 0