A 20.0-mH inductor is connected in series with a 100-Ω resistor at 1000 Hz. What is the phase angle of this circuit?
A) 90.0°
B) 51.5°
C) 38.5°
D) 0°
E) 45°

Question

Quizplus · Accepted Answer

The phase angle is given by:$$\phi = \arctan\left(\frac{2\pi f L}{R}ight)$$$$\phi = \arctan\left(\frac{2\pi (1000 	ext{ Hz})(20.0 	ext{ mH})}{100 \Omega}ight)$$$$\phi = 51.5°$$

A 200-MH Inductor Is Connected in Series with a 100-Ω Resistor