Find Brewster's angle for light reflected from the top of a water surface (n = 1.33).
A) 53.1°
B) 36.9°
C) 56.3°
D) 60.2°
E) 90.0°

Question

Quizplus · Accepted Answer

Brewster's angle is given by tan(theta_B) = n2/n1, where n1 is the index of refraction of the incident medium and n2 is the index of refraction of the refracted medium. In this case, n1 = 1 (air) and n2 = 1.33 (water), so tan(theta_B) = 1.33. Therefore, theta_B = 53.1°.

Find Brewster's Angle for Light Reflected from the Top of a Water