The focal length of the objective of a telescope is 75.0 cm. While the eyepiece has a focal length of 6.00 cm, what is the magnifying power of this telescope?
A) 0.0800
B) 0.645
C) 450
D) 12.5
E) 200

Question

Quizplus · Accepted Answer

The magnifying power of a telescope is given by the formula:

magnifying power = - (focal length of objective) / (focal length of eyepiece)

Substituting the given values, we have:

magnifying power = - (75.0 cm) / (6.00 cm) = -12.5

The negative sign indicates that the image is inverted. Therefore, the magnifying power of the telescope is 12.5.

So, the best choice is D.

The Focal Length of the Objective of a Telescope Is