In a two-slit experiment, the slit separation is 3.00 × 10^-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? A) 100 nm B) 204 nm C) 214 nm D) 224 nm E) 234 nm

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Quizplus · Accepted Answer

The distance between the bright fringes is given by:$$d = \frac{\lambda D}{d}$$where:d is the distance between the slitsD is the distance between the slits and the screenlambda is the wavelength of the lightWe are given that:d = 3.00 × 10^-5 mD = 2.00 mx = 10.0 cm = 0.100 mWe want to find:lambdaSubstituting the given values into the equation, we get:$$0.100 m = \frac{\lambda (2.00 m)}{3.00 	imes 10^{-5} m}$$Solving for lambda, we get:$$\lambda = 214 nm$$

In a Two-Slit Experiment, the Slit Separation Is 3