What is the energy of a photon that, when it is absorbed by a hydrogen atom, excites an electron from the ground state of the hydrogen atom to the n = 2 state? A) 10.2 eV B) 1.63 × 10^-18 J C) 1.63 × 10^-18 Nm D) All of the answers are correct. E) None of the answers is correct.

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Quizplus · Accepted Answer

The energy of a photon is given by E = hf, where h is Planck's constant and f is the frequency of the photon. The energy difference between the ground state and the n = 2 state of the hydrogen atom is given by the Rydberg formula: E = -13.6 eV / (n^2), where n is the principal quantum number. Therefore, the energy of a photon that can excite an electron from the ground state to the n = 2 state is E = -13.6 eV / (2^2) = 10.2 eV. This is equivalent to 1.63 × 10^-18 J or 1.63 × 10^-18 Nm.

What Is the Energy of a Photon That, When It