What is the wavelength of the emitted photon if an electron in the hydrogen atom makes a transition from n = 2 state to the ground state?
A) 121.5 nm
B) 203.1 nm
C) 243.0 nm
D) 388.8 nm
E) 411.1 nm

Question

Quizplus · Accepted Answer

The energy of the photon emitted during a transition from the n=2 state to the ground state (n=1) in hydrogen can be calculated using the Rydberg equation:

1/λ = R(1/n1^2 - 1/n2^2)

where λ is the wavelength of the photon, R is the Rydberg constant (1.097 x 10^7 m^-1), and n1 and n2 are the initial and final energy levels of the electron, respectively.

Substituting n1=2 and n2=1, we get:

1/λ = R(1/1^2 - 1/2^2) = 0.822 x 10^7 m^-1

Solving for λ, we get:

λ = 121.5 nm

What Is the Wavelength of the Emitted Photon If an Electron