If the heat of fusion for water is 80.cal/g,how many calories are needed to melt 45.0 g of ice at 0 °C?

Question

Quizplus · Accepted Answer

To calculate the heat required to melt ice (heat of fusion), we use the formula:

Q = m x ΔHf

where Q is the heat required (in calories), m is the mass of ice (in grams), and ΔHf is the heat of fusion (in cal/g).

Substituting the values given:

Q = 45.0 g x 80 cal/g
Q = 3600 cal

Therefore, the answer is 3.6 × 10^3 cal, which is closest to choice B.

If the Heat of Fusion for Water Is 80