At constant temperature,a sample of helium at 760.torr in a closed container was compressed from 5.00 L to 3.00 L.What was the new pressure exerted by the helium on its container?
A)800.torr
B)2280 torr
C)15.0 torr
D)3800 torr
E)1270 torr

Question

Quizplus · Accepted Answer

According to Boyle's Law (P1V1 = P2V2), the pressure and volume of a gas are inversely proportional at constant temperature. Using the initial conditions (P1 = 760 torr, V1 = 5.00 L) and the final volume (V2 = 3.00 L), the new pressure (P2) can be calculated as P2 = (P1V1)/V2 = (760 torr * 5.00 L) / 3.00 L = 1270 torr.

At Constant Temperature,a Sample of Helium at 760