The dehydration product of CH₃-CH₂ –O–H in the presence of acid is ________.

Question

Quizplus · Accepted Answer

The given compound has two alcohols which, on dehydration in the presence of acid, would result in the elimination of one molecule of water, thereby forming a double bond. The resulting product would have the same number of carbon atoms as the starting material. Hence, options B and C (which would result in a decrease in the number of carbon atoms) can be eliminated. Option E (propyne) would require the loss of 2 molecules of water which is not possible for the given starting material. The correct product would be CH₂=C=CH₂, which is propene (option D).

The Dehydration Product of CH3-CH2 –O–H in the Presence

The Dehydration Product of CH₃-CH₂ –O–H in the Presence