If the initial pressure of a system was 1.00 atm and the volume was halved and the kelvin temperature was tripled,what is the final pressure?

Question

Quizplus · Accepted Answer

Using the ideal gas law, $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the amount of substance, $R$ is the ideal gas constant, and $T$ is temperature in Kelvin. If the volume is halved ($V/2$) and the temperature is tripled ($3T$), the new pressure can be found by setting up the ratio $\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$. Substituting the changes gives $\frac{P_1V_1}{T_1} = \frac{P_2(V_1/2)}{3T_1}$, solving for $P_2$ gives $P_2 = 6P_1$. Therefore, if the initial pressure was 1.00 atm, the final pressure is 6.00 atm.

If the Initial Pressure of a System Was 1