What is the pressure of a 3.00 L gas vessel that has 18.0 grams of helium at ? (R= 0.0821 L atm/ mol K)

Question

What is the pressure of a 3.00 L gas vessel that has 18.0 grams of helium at  ? (R= 0.0821 L atm/ mol K)

Quizplus · Accepted Answer

First, we need to convert the mass of helium to moles using its molar mass (4.00 g/mol):

18.0 g He × (1 mol He / 4.00 g He) = 4.50 mol He

Next, we can use the ideal gas law to solve for pressure:

PV = nRT

P = nRT / V

P = (4.50 mol)(0.0821 L atm/mol K)(11°C + 273) / 3.00 L

P = 36.7 atm

Therefore, the pressure of the gas vessel is 36.7 atm. The correct choice is B.

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