At STP,12.69 g of a noble gas occupies 14.09 L.What is the identity of the noble gas? (R= 0.0821 L atm/ mol K)

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At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L. Using the ideal gas law, we can calculate the molar mass of the gas: PV = nRT, where P = 1 atm, V = 14.09 L, R = 0.0821 L atm/mol K, and T = 273 K. Solving for n (moles), n = PV/RT = (1 atm * 14.09 L) / (0.0821 L atm/mol K * 273 K) = 0.630 moles. The molar mass is then 12.69 g / 0.630 moles = 20.14 g/mol, which corresponds to Neon (Ne).

At STP,1269 G of a Noble Gas Occupies 14