A rigid cylinder contains 2.00 liters of gas at a temperature of 25°C.If the pressure of this gas is changed from 0.500 atmospheres to 1.50 atmospheres,what will be the new temperature (in Kelvin,reported to three significant figures)of the gas? (The volume is constant.)

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve this problem:

(P1/T1) = (P2/T2)

where P1 is the initial pressure, T1 is the initial temperature in Kelvin, P2 is the final pressure, and T2 is the final temperature in Kelvin.

Plugging in the values given:

(0.500 atm / 298 K) = (1.50 atm / T2)

Solving for T2:

T2 = (1.50 atm / 0.500 atm) x 298 K = 894 K

Therefore, the new temperature of the gas is 894 K (reported to three significant figures), which is choice D.

A Rigid Cylinder Contains 2