How many kJ of heat are needed to completely vaporize 23.4 g of H₂O? The heat of vaporization for water at the boiling point is 40.6kJ/mole.

Question

Quizplus · Accepted Answer

First, we need to find the number of moles of H₂O: molar mass of H₂O = 18.015 g/mol (approximate) number of moles = 23.4 g / 18.015 g/mol = 1.299 moles Next, we can use the heat of vaporization to find the amount of heat needed to vaporize this amount of water: heat needed = (1.299 moles) x (40.6 kJ/mol) = 52.8 kJ Therefore, the answer is B) 52.8.

How Many KJ of Heat Are Needed to Completely Vaporize