The titration of 25.00 mL a 0.125 M HClO₄ solution required 21.37 mL of KOH to reach the endpoint.What is the concentration of the KOH?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction between HClO and KOH is:

HClO + KOH -> KClO + H2O

From the stoichiometry of the reaction, we can see that 1 mole of KOH is required to react with 1 mole of HClO. Therefore, the number of moles of KOH used in the titration can be calculated using the following formula:

moles of KOH = Molarity of KOH x Volume of KOH used (in L)

Substituting the values given in the question, we get:

moles of KOH = Molarity of KOH x Volume of KOH used (in L)
moles of KOH = Molarity of KOH x 0.02137 L
moles of KOH = Molarity of KOH x 2.137 x 10^-2 mol

Since the number of moles of KOH used is equal to the number of moles of HClO present in the solution, we can use the following formula to calculate the concentration of HClO:

moles of HClO = moles of KOH
Molarity of HClO x Volume of HClO used (in L) = Molarity of KOH x Volume of KOH used (in L)

Substituting the values given in the question, we get:

Molarity of HClO x 0.02500 L = Molarity of KOH x 0.02137 L
Molarity of HClO = (Molarity of KOH x 0.02137 L) / 0.02500 L

Now, substituting the values given in the question, we get:

Molarity of HClO = (0.146 M x 0.02137 L) / 0.02500 L
Molarity of HClO = 0.1252 M

Therefore, the concentration of the KOH is 0.146 M.

The Titration of 25