A 3.6 mole sample of Co-60 has a half-life of 5.2 years.How many moles of Co is left after

Question

Quizplus · Accepted Answer

The formula for radioactive decay is:
N = N0 (1/2)^(t/T)
Where:
N = final amount
N0 = initial amount
t = time passed
T = half-life

We are given:
Initial amount (N0) = 3.6 moles
Half-life (T) = 5.2 years
Time passed (t) = 11 years

Substituting the values into the formula, we get:
N = 3.6 (1/2)^(11/5.2)
N = 0.11 moles

Therefore, the answer is B) 0.11.

A 36 Mole Sample of Co-60 Has a Half-Life of 5