A patient is treated on a 6-MV accelerator; field size is 10 x 12 cm and depth of tumor is 6 cm.What is the PDD?
A) 83.02
B) 83.18
C) 83.0
D) 83.2
Correct Answer:
Verified
Q17: Mayneord F factor is used in:
A) isocentric
Q18: As the field size increases,the TAR:
A) increases
B)
Q19: As the SSD increases,the PDD:
A) increases
B) decreases
C)
Q20: The equivalent square of rectangular field of
Q21: A patient is treated using two superiorly/inferiorly
Q23: What is the patient separation if depth
Q24: A patient is being treated on the
Q25: Adjacent fields that have an overlap at
Q26: Calculate the PDD of depth (d)if the
Q27: A patient is being treated on the
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