Complete the following nuclear equation: ?? ? $\begin{array} { c }
222\
86
\end{array}$ Rn + $\begin{array} { c }
4\
2
\end{array}$ He
A) $\begin{array} { c }
226 \
88
\end{array}$ Ra
B) $\begin{array} { l }
222 \
85
\end{array}$ At
C) $\begin{array} { c }
218\
84
\end{array}$ Po
D) $\begin{array} { c }
222\
86
\end{array}$ Rn
E)none of the above

Question

Complete the following nuclear equation: ?? ? $\begin{array} { c } 
222\
86
\end{array}$ Rn + $\begin{array} { c } 
4\
2
\end{array}$ He
A) $\begin{array} { c } 
226 \
88
\end{array}$ Ra
B) $\begin{array} { l } 
222 \
85
\end{array}$ At
C) $\begin{array} { c } 
218\
84
\end{array}$ Po
D) $\begin{array} { c } 
222\
86
\end{array}$ Rn
E)none of the above

Quizplus · Accepted Answer

The correct answer is $\begin{array} { c } 226 \ 88 \end{array}$ Ra because when it undergoes alpha decay, it emits a $\begin{array} { c } 4\ 2 \end{array}$ He particle, resulting in $\begin{array} { c } 222\ 86 \end{array}$ Rn. The atomic number decreases by 2 and the mass number decreases by 4, matching the given equation.

Complete the Following Nuclear Equation: ?? 22286\begin{array} { c } 222\\86\end{array}22286​

Complete the Following Nuclear Equation: ?? $\begin{array} { c } 222\\86\end{array}$