When $\begin{array} { c }
226 \
88
\end{array}$ Ra decays by emitting an alpha particle,what is the atomic number of the resulting nucleus? What is the resulting atomic mass?
A)atomic number = 86; atomic mass = 222
B)atomic number = 87; atomic mass = 226
C)atomic number = 86; atomic mass = 224
D)atomic number = 87; atomic mass = 224

Question

When $\begin{array} { c } 
226 \
88
\end{array}$ Ra decays by emitting an alpha particle,what is the atomic number of the resulting nucleus? What is the resulting atomic mass?
A)atomic number = 86; atomic mass = 222
B)atomic number = 87; atomic mass = 226
C)atomic number = 86; atomic mass = 224
D)atomic number = 87; atomic mass = 224

Quizplus · Accepted Answer

When $^{226}_{88}$Ra decays by emitting an alpha particle ($^{4}_{2}$He), the atomic number decreases by 2 (from 88 to 86) and the atomic mass decreases by 4 (from 226 to 222).

When 22688\begin{array} { c } 226 \\88\end{array}22688​ Ra Decays by Emitting an Alpha Particle,what Is the Atomic

When $\begin{array} { c } 226 \\88\end{array}$ Ra Decays by Emitting an Alpha Particle,what Is the Atomic