Why might the following nuclear reaction not be very good for energy production in a fusion reactor? $\begin{array} { l }
56 \
26
\end{array}$ Fe + $\begin{array} { l }
56 \
26
\end{array}$ Fe ? $\begin{array} { c }
112 \
52
\end{array}$ Te
A)The material only produces a few neutrons so the chain reaction will not be very efficient.
B)The reactants are too stable and it would cost energy to produce the product due to strong nuclear force.
C)The products are not the right size to obtain any energy from the missing mass due to the strong nuclear force.
D)The mass of the byproducts is too high and therefore the energy released will not be high enough.
E)Interatomic attraction between the products will impede the separation of the atoms from the unstable nuclei.

Question

Why might the following nuclear reaction not be very good for energy production in a fusion reactor? $\begin{array} { l } 
56 \
26
\end{array}$ Fe + $\begin{array} { l } 
56 \
26
\end{array}$ Fe ? $\begin{array} { c } 
112 \
52
\end{array}$ Te
A)The material only produces a few neutrons so the chain reaction will not be very efficient.
B)The reactants are too stable and it would cost energy to produce the product due to strong nuclear force.
C)The products are not the right size to obtain any energy from the missing mass due to the strong nuclear force.
D)The mass of the byproducts is too high and therefore the energy released will not be high enough.
E)Interatomic attraction between the products will impede the separation of the atoms from the unstable nuclei.

Quizplus · Accepted Answer

Fusion reactions are most efficient when they involve light nuclei, such as hydrogen isotopes, because these reactions can release a significant amount of energy due to the difference in binding energy per nucleon. Iron (Fe), with an atomic number of 26, is at the peak of the binding energy curve, meaning it is one of the most stable elements. Fusing iron or heavier elements consumes more energy than it releases, making it an inefficient process for energy production.

Why Might the Following Nuclear Reaction Not Be Very Good 5626\begin{array} { l } 56 \\26\end{array}5626​

Why Might the Following Nuclear Reaction Not Be Very Good $\begin{array} { l } 56 \\26\end{array}$